# Line slope calculator 4x-5y=16

**Straight line given by points A[4; 0] and B[9; 4]**

## Calculation:

**Slope-intercept form of line:**y = 0.8x-3.2

**Canonical form of the line equation:**4x-5y-16 = 0

**Parametric form of the line equation:**

x = 5t+4

y = 4t ; t ∈ R

**Slope:**m = 0.8

**Slope angle of line: φ =**38°39'35″ = 0.6747 rad

**X intercept:**x

_{0}= 4

**Y intercept:**y

_{0}= q = -3.2

**Distance line from the origin:**d

_{0}= 2.4988

**The length of the segment AB: |AB| =**6.4031

**Vector: AB =**(5; 4)

**Normal vector: n =**(4; -5)

**Midpoint of the segment AB: M =**[6.5; 2]

**Perpendicular Bisector equation:**5x+4y-40.5 = 0

**Vector OA = (4; 0) ; |OA| = 4**

**Vector OB = (9; 4) ; |OB| = 9.8489**

**Scalar product OA .OB = 36**

**Angle ∠ AOB = 23°57'45″ = 0.4182 rad**